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28s^2-27s=0
a = 28; b = -27; c = 0;
Δ = b2-4ac
Δ = -272-4·28·0
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-27}{2*28}=\frac{0}{56} =0 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+27}{2*28}=\frac{54}{56} =27/28 $
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